Math Homework Algebra 2?

The first one is asking you to use the y=mx+b (slope-intercept) form.

Just plug in your values.

m=slope=1/2

b=y-inter.=2

Your formula therefore is y=(1/2)x+2

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The second problem is asking for point-slope form (y-y1)=m(x-x1)

You are once again given the slope (m=slope=1) but this time you are given a random point, so....

x1 (given)=the point's x-value=2

y1 (given)=the point's y-value=-3

Plug them in and.....

y-(-3)=(1)(x-2) Voila!!!

You can shuffle things around a bit to get y=mx+b form, but it's not necessary.

(y=(x-2)-3=x-5)

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To write a line formula, you need the slope, and you know that (as a parallel line) the line you are looking for will have the same slope as the given line (x-y=4).

Shuffle things around a bit so that you isolate y.

-y=4-x

y=-4+x

The coefficient of x gives you the slope, and since x only has the imaginary coefficient of 1, that is your slope.

Now we get to use point-slope form again. Plug in your point.

y-6=(1)(x-1) <<<Again, it works, but if you want it to look like y=mx+b....

y=(x-1)+6=x+5

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|x+2|=4 >>> That give you two equations.

First: x+2=4

Second is the inverse, so pick a side and multiply it by -1. (I would choose the 4)

Second: x+2=-4

Now solve...

x+2=4>>>x=4-2=2

x+2=-4>>>x=-4-2=-6

Your answer is D.

1. y=1/2x+2(answer)

This one you have to calculate

-3=(1)2+b

b=-5

y=1x-5(answer)

2. x-y=4

y=x-4

1=(1)(6)+b

b=-5

y=1x-5(answer)

3. D