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Algebra/Geometry Help Please!?
Hero's formula for the area of a triangle is given by A = square root of [s(s-a)(s-b)(s-c), where a,b,and c are the lengths of the sides of the triangle and s= .5(a +b+c).
Find the lengths of the sides of the triangle given in this application of Hero's formula:
A = square root of (s^4 - 12s^3 + 47s^2 -60s)
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- Mike GLv 710 years agoFavorite Answer
A = sqrt(s^4 - 12s^3 + 47s^2 -60s)
A = sqrt [s(s-3)(s-4)(s-5)]
Sides are 3, 4 and 5
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