Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Physics Poewr problem?
When a single engine planes engine is at full power of 76kW, it gains altitude at 2.6m/s. The mass of the plane is 710kg. What fraction of the poewr is being used to make the plane climb. (The rest of the power overcomes the air resistance and inefficiencies in the prop and engine)
Please explain the equations as well, not just an answer. Thanks.
2 Answers
- oubaasLv 710 years agoFavorite Answer
76,000 watt = 76,000 j/sec = 76,000 Nm/sec
weight = mass*g = 710*9.8 = 6,958.00 N
power for climbing = weight*climbing speed = 6,958*2,6 = 18,090.8 watt
Fraction of the power used to make the plane climb :
100*18,090.8/76,000 = 23.8 %
- Anonymous10 years ago
The engine is producing 76000 Joules a second
The plane is gaining height energy at (m . g . h / s ) = 710 .9.8 . 2.6 = 18091 J / s
The fraction used to make the plane climb = 18091 / 76000 = 0.238 = 24%
Source(s): Old teacher
