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What mass of ammonia could be produced from this?
What mass of ammonia, NH3, could be produced from the reaction of 62.0 g of nitrogen, N2, and 10.3 g of hydrogen, H2:
N2 + 3 H2 -> 2 NH3
I am so stuck on this question. Please help. Please keep significant figures in mind.
1 Answer
- Roger the MoleLv 710 years agoFavorite Answer
N2 + 3 H2 → 2 NH3
(62.0 g N2) / (28.0134 g N2/mol) = 2.21323 mol N2
(10.3 g H2) / (2.0159 g H2/mol) = 5.10938 mol H2
5.10938 mole of H2 would react completely with 5.10938 x (1/3) = 1.70313 mol N2 but there is more N2 present than that, so N2 is in excess and H2 is the limiting reactant.
(5.10938 mol H2) x (2/3) x (17.0306 g NH3/mol) = 58.0 g NH3