Please help solve this algegra question:?

5a^2 - 14 = 3a

5a^2 - 3a - 14 = 0

5a^2 - 10a + 7 a - 14 = 0

5a (a - 2) + 7 (a - 2) = 0

(5a + 7) (a - 2) = 0

so 5a + 7 = 0 or a - 2 = 0

5a = -7 ............a = 2

a = -1.4 or 2

5a^2 -3a - 14 = 0 (get them all on the same side, then put them to zero.)

a = 5, b = -3, c = -14 (give a, b and c the value stated)

Then put it in the quadratic formula (seen here: http://www.google.co.uk/imgres?q=quadratic+formula... Sorry for long link!)

It comes down to x= (3 + square root of 289) / 10

or x= (3- square root of 289) / 10

Which is 2, or -1.4

I hope I helped, it's hard to explain the quadratic formula on here.

assuming equation is

5a^2 - 3a - 14 = 0

by quadratic formula where a= 5, b = -3, c = -14

x = (-b +/- √(b^2-4ac)) / 2a

x = (-(-3) +/- √((-3)^2 -4(5)(-14))) / 2(5)

x = (3 +/- √(9 - (-280))) / 10

x = (3 +/- √289) / 10

x = (3 +/- 17) / 10

x1 = (3 - 17)/10

x1 = -14/10

x = -7/5

x2 = (3 + 17)/10

x2 = 20/10

x2 = 2

THEREFORE x= -7/5, 2

5*a^2 - 3*a - 14 = 0

(5*a + 7)*(a - 2) = 0

a1 = - 7/5, a2 = 2