Could you help me anwser this algebra question:?

5b² - 14 -3b = 0

5b² -3b -14 = 0

5b² -10b + 7b -14 = 0

5b ( b - 2 ) +7 ( b - 2 ) = 0

( b - 2 ) ( 5b + 7 ) = 0

==> b = 2 and b = -7/5

Simplify the equation so it equals 0.

5b^2 -3b - 14 = 0

Because it is in this format (b^2 + b + an integer = 0), you can plug it into the Quadratic Formula.

After plugging "5", "-3", and "-14" into the equation, your answer will be x = 2 or x = -1.4

5b^2-14=3b

move 3b to the left side: 5b^2-3b-14=0

Use the quadratic formula: ax^2+bx+c=0, x= x= [-b+/-sqrt(b^2-4ac)]/2a.

so 5x^2-3x-14=0

b^2-4ac=(-3)^2-4*5*(-14)=9+20*14=289

so sqrt(289)=17

then x= [-(-3)+/-17]/10=

so x1=(3+17)/10=2; x2=(3-17)/10= -14/10= -7/5=-1.4

first subtract 3b from both sides of the equation so the equation equals zero.

5b^2-3b-14=0

then factor:

(5b+7)(b-2)

then set each one to zero

(5b+7)=0

b=-7/5

(b-2)=0

b=2

your answers should be: b= -7/2, b=2

5b^2 - 14 = 3b

5b^2 - 3b - 14 = 0

5b^2 -10b + 7b - 14 = 0

5b (b - 2) + 7 (b - 2) = 0

(5b + 7) (b - 2) = 0

so 5b + 7 = 0 or b - 2 = 0

.....5b = -7 or b = 2

.....b = -7/5 or 2