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- 10 years agoFavorite Answer
Either logx has a base of 10, or you forgot to enter it. My answer assumes it's base 10, but if it's not, just substitute my 10 for whatever the base of log x is.
dy/dx = (1/x)(logx) + (lnx)(1/ln10 * 1/x)
- 10 years ago
y'= lnx(10 ln x) + logx(1/x ) <product rule>
(I think its 10 since the base of log is 10 i think lol)
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