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2 Answers
- kbLv 710 years agoFavorite Answer
Assuming that m, n > 0.
(If m and/or n are negative, use sin(-t) = - sin t to remove the negative signs.)
The period of sin(nx) is 2π/n, and the period of sin(mx) is 2π/m.
==> The period of sin(nx) + sin(mx) is lcm(2π/n, 2π/m), if this exists.
Examples:
The period of sin(2x) + sin(3x) is lcm(2π/2, 2π/3) = 2π.
There is no period for sin(x) + sin(πx), because lcm(2π, 2) does not exist.
I hope this helps!
- ?Lv 710 years ago
sin nx + sin mx = 2 sin {(nx+mx)/2} cos{(nx-mx)/2}
Source(s): http://www.trans4mind.com/personal_development/mat... http://en.wikipedia.org/wiki/List_of_trigonometric... http://physicsformom.blogspot.com/2010/04/fourier-...