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how do you use cylindrical coordinates to solve for volume? (just explain)?
You don't have to have to answer though if you do i won't complain :), i just need an explanation on how to do this.
How do i use cylindrical coordinates to solve for volume of the set bounded by a the surface
z = 4 - x^2 + y^2 and the xy-plane is 8pi
1 Answer
- kbLv 710 years agoFavorite Answer
Note: I think you meant z = 4 - x^2 - y^2...
Cylindrical coordinates are defined by x = r cos t, y = r sin t, z = z.
So, z = 4 - x^2 - y^2 = 4 - r^2 cos^2(t) - r^2 sin^2(t) = 4 - r^2.
This intersects with the xy-plane (z = 0) when 0 = 4 - r^2 ==> r = 2, a circle.
So, the volume equals
∫∫ (4 - x^2 - y^2) dA
= ∫(r = 0 to 2) ∫(t = 0 to 2π) (4 - r^2) * r dt dr, converting to cylindrical coordinates
= ∫(r = 0 to 2) 2π * (4r - r^3) dr
= 2π * (2r^2 - r^4/4) {for r = 0 to 2}
= 8π.
I hope this helps!