can anyone help me with simplifying algebraic fractions and how to do them for tommorow please help?

let's start with the basic

4/x - 3/5

get a LOWEST common denominator of 5x by multiplying both fractions top and bottom by the parts the denominator doesn't currently have

5(4)/5x - x(3)/5x

[5(4) - x(3)] / 5x

(20 - 3x) / 5x

can't simplify further

2/3x - 5/4x^2

here, lowest common denominator is 12x^2:

4x(2)/12x^2 - 3(5)/12x^2

[4x(2) - 3(5)] / 12x^2

(8x - 15) / 12x^2

try something a little more complicated

3/(x-1) + 2/(x+1)

LCD is (x-1)(x+1):

(x+1)(3)/(x-1)(x+1) + (x-1)(2)/(x-1)(x+1)

[(x+1)(3) + (x-1)(2)] / (x-1)(x+1)

(3x +3 + 2x - 2) / (x-1)(x+1)

(5x +1) / (x-1)(x+1)

can't simplify further

and make it a little more interesting again

3/(x-1) + 2x/(x^2-1)

fully factor first!

3/(x-1) + 2x/(x-1)(x+1)

now see that our LOWEST common denominator is (x-1)(x+1):

(x+1)(3)/(x-1)(x+1) + 2x/(x-1)(x+1)

[(x+1)(3) + 2x] / (x-1)(x+1)

(3x + 3 + 2x) / (x-1)(x+1)

(5x + 3) / (x-1)(x+1)

can't simplify further

and one more complication

3/(x-1) - (3x +3)/(x^2-1)

fully factor

3/(x-1) - 3(x+1)/(x-1)(x+1)

NOTE that (x+1) / (x+1) = 1, leaving you with

3/(x-1) - 3(x+1)/(x-1)

we already have common denominators now, so just combine numerators

[3 - 3(x+1)] / (x-1)

(3 - 3x - 3) / (x-1)

-3x / (x-1)

can't simplify further

Say for example we have (2/(x + 3)) - (x/(x^2 - 9))

We can write this as (2/(x + 3)) - (x/((x + 3)(x - 3)))

We need a common denominator. We take the LCM of both denominators, multiply it by both numerators and put the result over the LCM, then simplify:

LCM = (x + 3)(x - 3). We don't need to change the second term as the denominator is the LCM, but the 2 must be multiplied with (x - 3) as that is the missing part in the denominator of that term. If we put all this over the LCM, we get:

(2(x - 3) - x)/((x + 3)(x - 3))

Now we simplify:

(2x - 6 - x)/((x + 3)(x - 3))

= (x - 6)/((x + 3)(x - 3))

http://www.mymaths.co.uk/

this will help just type in simpllifing algbraic fractions

i recommend you type an example next time :) good luck!

Give an example and we will try.