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angular momentum .... 10pts?
A 1.3kg particle moves in the xy plane with velocity of v=(4i-3j)m/s. Determine the angular momemtum of the particle about the origin when its position vector r=(3i+2j)
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- kuiperbelt2003Lv 79 years agoFavorite Answer
in vector form, angular momentum is m v cross r where cross is the vector cross product
the cross product of these two vectors is 17k, so the angular momentum is 1.3 x 17k kgm^2/s
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