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I need help with a trig problem?
I have to simplify this expression down to 2csc^2x
I started with 1/1+cosx + 1/1-cosx
Please help?
1 Answer
- 9 years agoFavorite Answer
1/1+cos(x) + 1/1-cos(x)
find common denominators
[1+cos(x)] * [1-cos(x)] = 1 - cos²(x)
[1-cos(x)]/[1-cos²(x)] + [1+cos(x)]/[1-cos²(x)]
= [1 - cos(x) + 1 + cos(x)] / [1 - cos²(x)]
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Trigonometric Identity:
1 - cos²(x) = sin²(x)
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= 2 / sin²(x)
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Trigonometric Identity:
1/sin(x) = csc(x)
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= 2csc²(x)
