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Give the answer in a + bi form?

-3 over 4 - i

I got -3 (4 - i ) over (4 - i) ( 4+i ) = -3 (4 - i ) over 4 ^2 - i ^ 2 = -3 ( 4 - i ) over 16 - ( - 1 ) = -3 ( 4 - i ) over 17 = -12 + 3 i over 17 = -12 over 17 + 3 over 17 i

when I got to the fraction part there was obviously no common denominator for 17 so i split it into two fractions...wrong.

2 Answers

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  • Jay
    Lv 5
    9 years ago
    Favorite Answer

    -3 / (4-i)

    multiply throughout by the conjugate of the denominator which is (4+i):

    -3(4+i) / (16-i^2)

    (-12-3i) / 17

    (-12/17) + (-3/17)i

  • 9 years ago

    ...-3

    -------

    4 - i

    ...-3....4 + i

    ------x-------

    4 - i....4 + 1

    -3(4 + i)

    ----------

    16 - i²

    -12 - 3i

    ----------

    16 - (-1)

    -12 - 3i

    ---------

    16 + 1

    -12 - 3i

    ----------

    ....17

    OR in a + bi form

    -12......3

    ----..-..--- i............ANSWER

    17.....17

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