Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

How do I set up this h=-16t^3+28t problem (see details)?

The height of an object tossed upward with an initial velocity of 12ft. per second is given by the formula: h=-16t^3+28t.

h is the height in ft.; t is the time in seconds

Find the time required for the object to return to its point of departure.

DO NOT give me the answer. Please explain how to set it up. It is an algebra course, not a physics course.

2 Answers

Relevance
  • 9 years ago
    Favorite Answer

    The height at t= 0 is h(0)=0

    To find the time to return to this height is to set h= 0 and solve for t:

    -16t^3+28t=0

    You will get three answers for t: one is negative (discard), one is zero, which you already knew.

    The third answer is the one you were looking for.

    Hoping this helps!

  • 9 years ago

    set h = 0 & solve for t

Still have questions? Get your answers by asking now.