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Can someone please solve this equation?
A baseball is thrown straight upward with an initial speed of 128 ft/sec. The number of feet s above the ground after t seconds is given by the equation
s = −16t^2 + 128t.
A. When will the baseball be 192 feet above te ground?
B. When will it hit the ground?
1 Answer
- ?Lv 79 years agoFavorite Answer
A. When will the baseball be 192 feet above the ground?
192= −16t^2 + 128t
−16t^2 + 128t-192=0
-16(t^2-8t+12)=0
-16(t-2)(t-6)=0
t=2sec. , t=6sec.
B. When will it hit the ground?
0= −16t^2 + 128t
-16t(t-8)=0
t=8 sec.
