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Calculus Integration by Parts?
No matter how many times I work this I can't figure it out.
INTEGRAL(x^3(1+x^2)^1/2)dx
This is what I've done
u=(1+x^2)^1/2 dv=x^3
du=x(1+x^2)^-1/2 v=x^4/4
So,
(x^4/4)(1+x^2)^1/2- INTEGRAL((x^4/4)x(1+x^2)^-1/2)
This is where I'm stuck. I have to take the integral again, but once I do I have to take it again and again. It's an endless chain. Please don't tell me the answer, but if you could point me in the right direction, that would be fantastic. Also, if anyone knows about like a free online tutor for calculus or something let me know. Thanks.
2 Answers
- Anonymous5 years ago
You did the integration correctly; just evaluate it at x = 1/2 and subtract from the the your results evaluated at x =0.
