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First order nonlinear differential equation help?
First order nonlinear differential equation help?
i need help solving this equation please im stumped. included any step also. thanks
5y^4 y'= xy'+y
1 Answer
- RapidfireLv 79 years agoFavorite Answer
Rewrite this differential equation by rearranging then flipping the derivative:
5y⁴y'= xy' + y
5y⁴(dy / dx) = x(dy / dx) + y
5y⁴(dy / dx) - x(dy / dx) = y
(5y⁴ - x)(dy / dx) = y
dy / dx = y / (5y⁴ - x)
dx / dy = (5y⁴ - x) / y
dx / dy = 5y³ - x / y
Solve this differential equation by using an integrating factor:
dx / dy + x / y = 5y³
dx / dy + P(y)x = f(y)
P(y) = 1 / y
f(y) = 5y³
I(y) = ℮^[∫ P(y) dy]
I(y) = ℮^(∫ 1 / y dy)
I(y) = ℮^(ln|y|)
I(y) = y
xy = ∫ I(y)f(y) dy
xy = ∫ 5y⁴ dy
xy = y⁵ + C
x = y⁴ + C / y