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An ESL Learner
Lv 7
An ESL Learner asked in 科學及數學數學 · 9 years ago

一 6 位正整數，由 2 個不同的非零數字組成，分別佔 2

一 6 位正整數，由 2 個不同的非零數字組成，分別佔 2 個及 4 個位，共有多少個可能？

THX!

2 Answers

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  • ☂雨後晴空☀
    Lv 7
    9 years ago
    Favorite Answer

    2 個不同的非零數字及佔位個數選擇 : 9P2

    6個數排列 : 6! / (2! * 4!)

    9P2 * 6! / (2! * 4!)= 1080 個可能。

  • 地獄之王者-冥王哈帝斯
    Lv 4
    9 years ago

    計算方法: 9P2( 2 個不同的非零數字的可能)x6!/(2!x4!)

    (6個數排列)

    6!=6x5x4x3x2x1=720

    2!x4!=2x1x4x3x2x1=48

    9P2 x 6! / (2! x 4!)=1080個不同的可能性

    希望我可以幫到你.

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