2y+8x=10...........Eq,1.And 4y+x=20........Eq,2.Find x?.?

there are two methods

Method one:

isolate one variable and plug it's value into the second equation

2y+8x=10

2y=10-8x

y=5-4x

plug into 4y+x=20

4(5-4x)+x=20

20-16x+x=20

20-15x=20

0=15x

x=0

Method two:

add or subtract the equations so that one variable cancels out

2y+8x=10 multiplied by 2 is 4y+16x=20

subtract the second equation 4y+x=20 from this equation

4y+16x=20

-(4y+x=20)

4y+16x=20

-4y-x=-20

--------------

15x=0

x=0

you could also isolate y in both equations and set the expressions for y equal to eachother:

2y+8x=10

2y=10-8x

y=5-4x

4y+x=20

4y=20-x

y=(20-x)/4

y=y

5-4x=(20-x)/4

20-16x=20-x

20=20+15x

0=15x

x=0

2y+8x=10...........Eq,1.

4y+x=20.............Eq,2

Multiply Eq1 with 2

4y+16x=20

subtract from Eq2

x-16x= 20- 20=0

-15x=0

x=0

From Eq2

4y+x=20

4y+0=20

y=5

in eq 1 put y subject of the formula : y=(10-8x)/(2)

substitude y of eq 1 in eq 2 : 4((10-8x)/(2)))+x=20

40-16x+x=20

-15x=-20

x=20/15 thats the answer.

8x+2y=10 ----(1)x2

x+4y=20 -------(2)

16x+4y=20 ----(3)

x+4y=20 ------(4)

- - -

----------------

15x = 0

x=0