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Let X =1/1001+1/1002+...+1/3001.Then which is correct (A)X>1 (B)X<3/2 (C)1<X<3/2 (D)none of the above holds?
this is an inequality problem . please help me.
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- Kali PrasadLv 69 years agoFavorite Answer
this is Riemann sum integral of 1/ x from 1000 to 3001
which is ln x from 1000 to 3001 which is ln 3001 - ln 1000 = ln 3.1
if is between 1 and 3/2 so (C)
Source(s): http://en.wikipedia.org/wiki/Riemann_sum
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