help with nth terms mathmatics?

what's the nth term given as? It aint that clear. However, this is how to go about it.

For the first term, n=1. So put 1 in place of n and solve to get the first term.

For the second and third terms , n=2 and n=3 respectively so you put 2 and 3 in place of n and solve to get the second and third terms of the sequence as well.

n=where abouts the number is in the sequence

the 1st number in the sequence means that n=1

the 2nd number in the sequence means that n=2

the 3rd number in the sequence means that n=3

and so on for infinity.

So the first three terms?

the 1st term n would be 1, because it is the 1st number in the sequence, thus

3x1quared=3 + 2x1=5 , this is because i substituted n for 1

2nd term means n would be 2, so substitute n for 2

3x2 squared=12 + 2x2=16

the 3rd term, n would be 3

3x3 squared=27 + 2x3=33

3x3squared=27 as with the rules of BIDMAS, you do indices first

bhoo

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