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Can someone help me solve this trig ID?
cot^2a=cos^2a+(cota*cosa)^2
^2= squared
3 Answers
- GeronimoLv 79 years agoFavorite Answer
cot²a = cos²a + (cota • cosa)² ... reduce to sines & cosines only
cos²a ⁄ sin²a = cos²a + [ (cosa ⁄ sina) • (cosa) ]²
cos²a ⁄ sin²a = cos²a + [ cos²a ⁄ sina ]²
cos²a ⁄ sin²a = cos²a + [ cos^4(a) ⁄ sin²a ] ... multiply by sin²a
cos²a = [ sin²a • cos²a ] + cos^4(a) ... factor: cos²a
cos²a = cos²a • [ sin²a + cos²a ]
1 = sin²a + cos²a ... identity
- Anonymous4 years ago
I have been given 2*tan(theta): [(sin(theta)-a million)^2-cos^2(theta)]/cos(th... (liquid crystal demonstrate and including the fractions). enhance the numerator: sin^2(theta)-2sin(theta)+ a million -cos^2(theta). (a million-cos^2(theta)=sin^2(theta), so the numerator turns into: 2sin^2(theta)-2sin(theta). ingredient out the 2sin(theta) and the entire fraction is: [2sin(theta)*(sin(theta)-a million)]/[cos(theta)... The (sin(theta)-a million) cancels and you're left with 2sin(theta)/cos(theta), the place sin(theta)/cos(theta)=tan(theta). desire this is what you're searching for. good luck ^_^
