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What is the minimum area (in square meters) of the top surface an ice slab 0.450 m .. ?
What is the minimum area (in square meters) of the top surface an ice slab 0.450 m thick floating on fresh water that will hold up a 1140 kg automobile? Take the densities of ice and fresh water to be 917 kg/m3 and 998 kg/m3, respectively.
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1 Answer
- oldschoolLv 79 years agoFavorite Answer
The mass of the water displaced must equal the mass of the ice plus the mass of the car. Let the area be A. The thickness of the slab is 0.450 so the volume of the slab is A*0.450
A*0.450*998 = A*0.450*917 + 1140
A = 1140/0.450[998-917] = 31.276m^2