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Integration using the U Substitution?

I am really not understanding this two problems. thanks for the help

1. 1/sqrt x (1+sqrtx)^2

2. r^2 (r^3/18 - 1)^5 dr

1 Answer

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  • Anonymous
    9 years ago
    Favorite Answer

    1. u=1+sqrtx, du=1/(2sqrtx)

    So you have 2u^2 du

    Integrates to 2(u^3)/3

    Plug in u=1+sqrtx

    2[(1+sqrtx)^3]/3

    2. u=(r^3)/18-1, du=(r^2)/6

    So you have 6u^5 du

    Integrates to u^6

    Plug in u=(r^3)/18-1

    [(r^3)/18-1]^6

    Source(s): dinosaur
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