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Evaluate the definite integral?
Having trouble with this part of my homework.
1. t sqrt( t^2+1dt) bounded by [0,sqrt7]
2. 4x/sq(x^2+1) dx [-sqrt3, sqrt3]
thank you for the help
1 Answer
Relevance
- Geeganage WLv 59 years agoFavorite Answer
ʃt√( t^2+1)dt bounded by [0,√7] =(1/3)[t^2+1]^(3/2) from [0,√7] =(1/3)[16√2 -1]
ʃ4x/√(x^2+1) dx; [-√3, √3] = 4[√(x^2+1)] from [-√3, √3] = 4√(4-4) =0
Source(s): ʃf '(x)[f(x)]^ndx = {[f(x)]^(n+1)}/(1/(n+1) +C; where n≠ -1 ʃ{(1/2)f '(x)/√[f(x)]}dx = √[f(x)] +C
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