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Taz
Lv 5
Taz asked in Science & MathematicsChemistry · 9 years ago

How to find the maximum yield?

2(Al) + 3(CuCl2) => 2(AlCl3) + 3(Cu)

Al: 0,40g

CuCl2 H2.: 5,01g

With these formulas, I was wondering how to figure out the maximum yield with CuCl2 in excess.

2 Answers

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  • 9 years ago
    Favorite Answer

    Basic equation I've used for several years is this:

    moles (limiting reagent) x Molecular Weight (product) = grams (theoretical max product yield)

    Keep in mind though the ratio of the reaction tho, in your case it is 2:2 so its simple. (For AlCl3 prediction)

    .4g Al = .0148moles Al and AlCl3 MW is 133.34 so....

    .0148*133.34 = 1.977g would be your maximum possible yield aka theoretic yield of AlCl3

    Source(s): Associates in Science
  • Anonymous
    4 years ago

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