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How to find the maximum yield?
2(Al) + 3(CuCl2) => 2(AlCl3) + 3(Cu)
Al: 0,40g
CuCl2 H2.: 5,01g
With these formulas, I was wondering how to figure out the maximum yield with CuCl2 in excess.
2 Answers
- 9 years agoFavorite Answer
Basic equation I've used for several years is this:
moles (limiting reagent) x Molecular Weight (product) = grams (theoretical max product yield)
Keep in mind though the ratio of the reaction tho, in your case it is 2:2 so its simple. (For AlCl3 prediction)
.4g Al = .0148moles Al and AlCl3 MW is 133.34 so....
.0148*133.34 = 1.977g would be your maximum possible yield aka theoretic yield of AlCl3
Source(s): Associates in Science - Anonymous4 years ago
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