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f(x)=log3x, the log base is 3. How is this solved and what would some coordinates be?
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- I'm with StupidLv 79 years agoFavorite Answer
f(x) = log_3(x)
let x = integer powers of 3
so
f(1/9) = -2
f(1/3) = -1
f(1) = 0
f(3) = 1
f(9) = 2
etc.
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