Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Math ( Rewrite the expression as a single logarithm )?
a) 6 log x - 1/4 log y + log z
b)1/2 log x - 3 log y - 2 log z
4 Answers
- 9 years ago
a) 6 log x - 1/4 log y +log z remember, log a + log b = log (ab) and a log b = log a^b ,
log a - log b=log a/b ^ = to the power of which you probably know
so log x^6 - log y^(1/4) + log z= (log zx^6/y^1/4)
b)1/2 log x - 3 log y - 2 log z = log x^1/2 - log y ^ 3 - log z^2= log (x^1/2 / y^3) - log z^2 =
log( x^1/2 / y^3 z^2)
This is my first answered question so I hope its good
Source(s): currently in Pre-Calculus - Davis PLv 79 years ago
a) 6 log x - 1/4 log y + log z
log x^6 - log y^(1/4) + log z
log ( x^6 z /y^(1/4) )
b)1/2 log x - 3 log y - 2 log z
log x^(1/2) - log y^3 - log z^2
log ( sqrt(x) / ( y^3 z^2 ) )
- Anonymous9 years ago
a)log((x^6*z)/y^(1/4))
b)log(x^(1/2)/(y^3*z^2))
- ?Lv 44 years ago
Use formulation - log a + log b = log (ab) for all. a million) 4log x - 2log(x^2+a million)+4log(x-a million) = log x^4 - log (x^2 + a million)^2 + log (x-a million)^4 = log [ x^4 * (x^2 + a million)^2 * (x-a million)^4 ] A = [ x^4 * (x^2 + a million)^2 * (x-a million)^4 ] 2) ln (a+b) + 5 ln (a-b) - 3lnc = ln (a+b) + ln (a-b)^5 - ln c^3 = ln [ (a+b) * (a-b)^5 * c^3] A = [ (a+b) * (a-b)^5 * c^3]
