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maths extended trigonometry. trigonometrical identities?

Solve for value of x between 0 degrees and 360 degrees

a) 2sinx=cos(x+60)

b) cos(x+45)=cosx

c) sin(x-30)=1/2cosx

d) 3sin(x+10)=4cos(x-10)

2 Answers

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  • Ed I
    Lv 7
    9 years ago
    Favorite Answer

    a) 2 sin x = cos (x + 60°) = cos x cos 60° - sin x sin 60° = 1/2 cos x - √3/2 sin x

    (2 + √3/2) sin x = 1/2 cos x

    tan x = 1/(4 + √3)

    x ≈ 9.90° or 189.90°

    b) cos (x + 45) = cos x

    cos x cos 45° - sin x sin 45° = cos x

    cos x (√2/2 - 1) = √2/2 sin x

    (√2/2 - 1)/(√2/2) = tan x

    1 - √2 = tan x

    x = 157.5° or 337.5°

    c) sin (x - 30°) = 1/2 cos x

    sin x cos 30° - cos x sin 30° = 1/2 cos x

    √3/2 sin x = cos x

    tan x = 2/√3

    x ≈ 49.1°, 229.1°

    d) 3 sin (x + 10°) = 4 cos (x - 10°)

    3 sin x cos 10° + 3 cos x sin 10° = 4 cos x cos 10° + 4 sin x sin 10°

    (3 cos 10° - 4 sin 10°) sin x = (4 cos 10° - 3 sin 10°) cos x

    tan x = (4 cos 10° - 3 sin 10°)/(3 cos 10° - 4 sin 10°)

    tan x = 1.5126...

    x ≈ 56.5°, 336.5°

  • 9 years ago

    a) 2sinx=cos(x+60)

    => 2 sin x = (1/2)cos x - ( √3/2) sin x

    multiply with 2

    => 4 sin x + √3 sin x = cos x

    sin x (4 + √3) = cos x

    divide by cos x

    tan x (4 + √3) = 1

    tan x = 1 /(4 + √3) = (4 -√3) /13

    x = 9.9° and 189.9 °

    b) cos(x+45) = cosx

    => cos(x + 45) = cos(360 - x)

    => ( x + 45) = 360 - x

    => 2x = 315

    x = 315/2 = 157.5°

    c) sin(x-30)=1/2cosx

    =>√3/2 sin x - 1/2 cos x = 1/2 cos x

    => √3 sin x = 2 cos x

    divide by cos x

    tan x = 2/√3

    x = 49.11° and 229.11°

    d) 3sin(x+10 ) = 4cos(x-10)

    3(sin x cos 10 + cos x sin(10)) = 4( cos x cos 10 + sin x sin 10)

    => 2.9544 sin x + 0.5209 cos x = 3.939 cos x + 0.695 sin x

    =>2.2594 sin x = 3.4181 cos x

    => tan x = 1.5128

    x = 56.5349° and 236.5349°

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