Intermediate Algebra Question!?

1a) (5,-3) (3,-7)

distance = √((x2-x1)^2 + (y2-y1)^2)

Put in the values of the points:

distance = √((3-(5))^2 + (-7-(-3))^2)

= √((3-5)^2 + (-7-(-3))^2)

= √((-2)^2 + (-7-(-3))^2)

= √(((4)) + (-7-(-3))^2)

= √((4) + (-7-(-3))^2)

= √((4) + (-7+3)^2)

= √((4) + (-4)^2)

= √(4 + 16)

= √(20)

= 2√(5)

b) midpoint = (x1+x2)/2, (y1+y2)/2

Put in the values given:

= (5+3)/2, (-3-7)/2

= (4,-5)

2) a) 16x + 16 +4x +6y - 3 = 0

20x + 6y + 13=0

6y = -20x - 13

y = (-20x-13)/6

This is a line.

b) 16x + 4y - 3 = 0

This is similar to the previous problem, and it is a line.

c) 16 + 4 +4x +6y - 3 = 0

Line

d) 16 + 16 +4x +6y - 3 = 0

Line

e) 16 - 16 +4x +6y - 3 = 0

Line

each college district might have a distinctive theory of what's "Introductory Algebra" and "Intermediate Algebra". those are actually not maths words; they're names of instructions. each type has a written syllabus which says what you may desire to comprehend on the tip of the three hundred and sixty 5 days. Ask your instructor for a replica; its not a secret. have a seem. additionally, maximum instructions use a textbook; ask your instructor what textbook is used and what chapters are lined and circulate to the library and characteristic a seem for your self. in case you recognize just about each and all of the fabric, you would be surprisingly bored just about each and all of the time, so pass it. Oh, and BTW, via any standards getting ninety 8.87% skill you're reliable at maths. start up making use of that as foundation for questioning approximately your destiny education. that's probable why you have been given the possibility to pass a topic; in the experience that your instructors think of you may handle it, you very just about unquestionably can; instructors are very conservative in making those techniques.