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Intermediate Algebra Question!?
Rewrite the equation in the standard form of a parabola. Use (x-h)^2 =a(y-k) Plese show work.
1. y^2 - 8y + 16x -16 = 0
3 Answers
- ireadlotsLv 69 years agoFavorite Answer
Start by getting your x's and y's on opposite sides
y^2-8y = -16x+16
Notice that it is the y term that is squared, so we have a sideways parabola, with an equation in the form (y-k)^2 = a(x-h)... (h,k) is the vertex.
Complete the square for the y term
y^2 -8y + (-8/2)^2 = -16x + 16 + (-8/2)^2
(y-4)^2 = -16x + 16 + 16
(y-4)^2 = -16(x-2)
The parabola has vertex at (2,4)
- Anonymous9 years ago
y^2 - 8y = -16x +16
y^2-8y+16 = -16x +16 +16 = -16x+32
(y-4)^2 = -16(x-2)
