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y=kx and y=kxz question?
Could somebody show step by step how to solve the following two problems? Thanks!
Given that y varies inversely as x, write an inverse-variation equation when y=18 and x=3. Then using the inverse variation equation, find y when x=9.
and
Given that y varies jointly as x and z, write a joint-variation equation when y=2, x=(1/4), and z=(1/2). Then using the joint variation equation, find y when x=7 and z=(1/8)
1 Answer
- ?Lv 79 years agoFavorite Answer
y varies inversely as x --> y = K / x where K is a constant
"Inversely" means out it into the denominator
Use your knowns to solve for K, then do the 2nd part of the problem
18 = K / 3 --> K = 3(10)= 54
y = 54/ 9 --> y = 6
y varies jointly as x and z --> y = Kxz where K is a constant
"jointly" means the variables go into the numerator
Use the knowns to solve for K then do the snd part of the problem
2 = K(1/4)(1/2)
2 = K/8 --> K = 16
y = 16 (7)(1/8) --> y = 14