Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Intermediate Algebra please help?

Write the expression as a sum and/or differerence of multiple of logarithms,

1. In(ex^2/ysquare root z

2.log(100x^2z)

Write the expression as a single logarithm with coefficent 1.

1. 1/2logx-logy+3log(x-3)

2.log2(x^2-5x+6)-log2(x^2-4)+log2(x+2)

1 Answer

Relevance
  • 9 years ago
    Favorite Answer

    Some rules of logarithms:

    log a*b = log a + log b

    log a/b = log a - log b

    log a^n = n * log a

    So for the third expression you listed: 1/2logx-logy+3log(x-3) let's split it up into three pieces: 1/2logx, logy, and 3log(x-3)

    1/2 log x can be written as log x^(0.5)

    3 log (x-3) can be written as log (x-3)^3

    Recombining, we get:

    log x^0.5 - log y + log (x-3)^3

    Now, you can apply the rules above:

    log [(x^0.5) * (x-3)^3] / y

    Similar machinations for the fourth expression.

    The first expression you listed does not appear complete/correct. There is a missing ")" and it's not clear where the sqrt(z) goes.....

    The second expression can also use the rules:

    log (100*x^2z) = log 100 + log x^2z = 2 + (2z * log x)

    (Do you see why log 100 was replaced by 2?)

Still have questions? Get your answers by asking now.