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Hugo
Lv 5
Hugo asked in Science & MathematicsChemistry · 9 years ago

one liter of HCl 0.01 M is dissolved in a million liters of pure water, what is the pH of this final solution?

somebody says PH=8 as it is at the end HCl 10^-8 M

but it can get basic by adding acid

2 Answers

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  • 9 years ago
    Favorite Answer

    0.01M = 10^-2 WHEN IT IS DISSOLVED IN 10^6 LITRES OFWATER THEN

    [H+] = 10^2/10^6 = 10^-8

    note------------- now we have to take into consideration the [H+] concentration of water '

    i. e. total [H+] = 10^-8+ 10^-7

    = 10^-8[1+10]

    = 11x10^-8

    so pH = - log[11x10^-8]

    = 8 - log11

    = 8 - 1.041 = 6.958 ANWER [ it is 100% correct .]

    so the solution is acidic . [ pH< 7 so acidic ]

    Source(s): i am M.Sc. chem. 1973 & ex-examiner . and expert in chemistry
  • luella
    Lv 4
    5 years ago

    First you must to find the attention of HCl M=moles/liters M=2/1 M=1 pH=-log([H+]) when you consider that all the HCl will dissociate, you have the same attention of H+ as you do for HCl so pH=-log(2) pH=-.301 it is bad on account that that's how pH is measure thoratically nearly, that would no longer be the answer

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