Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Please help? Algebra 2? ASAP?
What is the 23rd term of the arithmetic sequence where a1 = 8 and a5 = 22?
A) 65
B) 77
C) 85
D) 97
What is the 32nd term of the arithmetic sequence where a1 = 14 and a13 = -58?
A) -178
B) -172
C) -166
D) -160
What is the 32nd term of the arithmetic sequence where a1 = -34 and a9 = -122?
A) -408
B) -397
C) -386
D) -375
2 Answers
- sahsjingLv 79 years agoFavorite Answer
1.
4d = 22-8 = 14
d = 3.5
a23 = a1+22d = 8+22*3.5 = 85
Answer: C
2.
12d = -58-14
d = -6
a32 = a1+31d = 14+31(-6) = -172
Answer: B
3.
8d = -122+34
d = -11
a32 = a1+31d = -34+31(-11) = -375
Answer: D
- Anonymous4 years ago
sparkling up for the two x or y in the two equation then plug what you get in the different equation for that comparable variable. as an occasion: a million.12x=3.sixty 4+a million.4y->divide the two factors by ability of a million.12 after which you get x=(3.sixty 4/a million.12)+(a million.4y/a million.12) (Sorry, i don't have a calculator). Plug that final equation in for x and then slove for y. once you sparkling up for y interior the precise equation plug it in in the different equation and locate x.
