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Algebra Intermediate Question!?
Graph f(x) = Square root x-2 + 1 and state the domain and range. I know you can't show me how to graph but I need help on the set up to figure out which points I need, please show work thank you.
1 Answer
- vahucelLv 69 years agoFavorite Answer
Write the function so: f(x) = sqrt(x-2) + 1
There are some information about the graph of a function that will help here.
a) If you know the graph of a function f(x) then the graph of f(x) + k is the same graph moved k steps up if k is positive and k steps down if k is negative.
b) If you know the graph of a function f(x) then the graph of f(x+k) is the same graph moved k steps to left if k is positive and k steps right if k is negative.
Here it was used the tow property... the graph of f(x) = sqrt(x-2) +1 is the same graph of
f(x) = sqrt(x) but 2 steps moved to right and 1 step moved to up.
Graph the function f(x) = sqrt(x) and change the origin (0,0) to the point (2,-1) and graph the new x-axis and y-axis... OK!
The domain of f(x) = sqrt(x-2) + 1 is x>=2 and the range is y>= -1 OK!
