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logarithmic differentiation?
y = x sqrt(x^2+12), x>0
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- izelkayLv 69 years agoFavorite Answer
That's not logarithmic differentiation, it's simply differentiation using the product rule and chain rule.
y = x√(x^2+12)
y' = √(x^2+12) + [x^2/√(x^2+12)]
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