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Please help me with this Math Problem?
How many gallons of a 90% antifreeze solution must be mixed with 100 gallons of 15% antifreeze to get a mixture that is 80% antifreeze?
Can someone show me your work to figure out the answer to this question? I cannot figure out the equation to write for this type of equation. (You won't just be giving me the answer. It will help me see how to do it. It will give me different numbers to work with next time.
Ali, no. They are antifreeze solutions. So the antifreeze is diluted.
3 Answers
- ?Lv 59 years agoFavorite Answer
You have x gallons of 90% antifreeze solution, and 100 gallons of 15% antifreeze solution. When you add them together, you want the amount of antifreeze to equal 80% of x + 100 gallons.
0.9x + (0.15)(100) = 0.8(x + 100)
0.9x + 15 = 0.8x + 80
0.1x = 65
x = 650
Check:
(0.9)(650) = 585 gallons of antifreeze
(0.15)(100) = 15 gallons of antifreeze
total gallons = 650 + 100 = 750
total gallons of antifreeze = 585 + 15 = 600
600 / 750 = 0.8 = 80%
- 9 years ago
First of all if you mix two antifreeze's together your just going to get more antifreeze. but that's besides the point.
Well you need to figure out, If you had one gallon of 15% how much 90% would you put in?
then i would think that you would multiply that answer by 100?
- utoenjoy2000Lv 49 years ago
C1 / C2 = V2 / V1
C1 concentration of stock
C2 concetration needed
V1 volume of stock
V2 volume needed
