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What would you like to ask?Help with solving trigeonometric equation?
Need help with solving this equation. Pretend W is theta.
4sin^2 W tanW minus tanW=0
With interval of [0, 2pi]
So far, I start with this: tanW(4sin^2 W minus 1) = 0
Is that good or I have to turn tan in sinW over cosW or what?
1 Answer
- GlenguinLv 79 years agoFavorite Answer
4sin²θ tanθ - tanθ = 0;
Factor tanθ:
tanθ (4sin²θ - 1) = 0;
Divide both sides by tanθ:
4sin²θ - 1 = 0;
Add 1 to both sides then divide both sides by 4:
4sin²θ = 1;
sin²θ = 1/4;
Take the square root of both sides:
sinθ = 1/2.
θ = sin^-1(1/2) = 30° and 150°, or π/6 and 5π/6 radians.
