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aromatic compounds help?
I'm trying to figure out if a certain compound is aromatic but I'm having trouble. I understand the 2 criteria for determining aromaticity but my issue is this: what if you have a cyclic compound but there is a double bond on the outside of the ring? As in one of the carbons are in the ring but the other carbon is not attached to anything? Does that effect the conjugated system?
Or what if you draw the cyclic compound and when you add the second line for the double bond on one of the sides, it's also outside of the ring instead of being drawn inside of the ring? Does that effect the conjugated system?
I'm sorry if this seems confusing but any help would be fantastic!
2 Answers
- kumorifoxLv 79 years agoFavorite Answer
As soon as one of the carbons on the ring has an external double bond, aromaticity is not possible. You may get resonance structures, but they are generally not stable, meaning the molecule is not truly aromatic. Quinones are examples, 6-membered rings with 2 carbonyl groups. They are derived from aromatic compounds, and some of them have aromatic parts (such as 1,4-naphthylquinone), but the part with the carbonyl groups can no longer be aromatic due to the cyclic structure not being conjugated any longer.
- 5 years ago
A hydrocarbon containing one or more benzene rings which are attribute of the benzene series of compounds Aromaticity is a chemical property in which a conjugated ring of unsaturated bonds, lone pairs, or empty orbitals showcase a stabilization more advantageous than would be anticipated by the stabilization of conjugation by myself. It can also be viewed a manifestation of cyclic delocalization and of resonance. Any compound which exhibits aromaticity A compound containing an fragrant ring. Fragrant compounds have strong, characteristic odours.
