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I need help with pharmacy math, more specifically, Algorithms?

Any help would be greatly appreciated!

Here is the problem (it's long):

You need to prepare a topical solution with a final product. Prepare a 1 liter IV bag with a 27% concentration of product x. The strengths available are 50%, 70%, and 10%.

Questions:

1) How many parts of the 10% solution will be required?

2) How many parts of the 70% solution will be required?

3) How many parts of the 50% solution will be required?

4) If the final product is to be a total volume of 1 liter how many milliliters of the 10% solution will be required?

5) If the final product is to be a total volume of a liter how many milliliters of the 50% solution will be required?

6) If the final product is to be a total volume of a liter how many milliliters of the 70% solution will be required?

1 Answer

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  • 9 years ago
    Favorite Answer

    You only need 2 of the solutions. One greater than 27% and one less than 27%. I choose 10% and 50% so my answer to question #2 is 0 parts and question #6 is 0ml.

    This is a classic alligation problem. Ignore the dots.

    50................ 17parts (27-10)

    .........27.....................[final concentration]

    10................ 13parts (50-27)

    .................... ----------

    .................... 30parts total

    All that means is your final solution will need 17parts of 50% and 13parts of 10%. [this answers 1 and 3]

    Now the math....

    You need to make 1000ml which equals 30parts

    1000ml/30parts = 33,33ml/part

    How much 50%: 33.33ml/part * 17parts = 566.61ml [answers #5]

    How much 10%: 33.33ml/part * 13parts = 433.39ml [answers #4]

    PS: You can also do it using the 70% and 10%. Same procedure.

    Source(s): Pharmacist
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