Log problem (non-10 base)?

Take logs on both sides > log(9375)=log(1/2)^n Then you take down the power n to get log(9375)=nlog(1/2) then you just divide both sides by log(1/2) to get the final answer to be: n=log(9375)/log(1/2)

Take the log of both sides.

Log .9375=log(1/2) n

n=log.9375/log.5

Just a small hint since all the above users have answered your queries

log (base c) A / log (base c) B = log (base b) A

Example log (base 2) 4 = log (base 10) 4 / log (base 10) 2 = 2

if you use base 2 then log (base 2) 4 = log (base 2) 2² = 2 log (base 2) 2

we know log (base a) A is always 1 , therefore 2 log (base 2) 2 = 2 * 1 = 2 which is the same as we did when we converted to base 10.

ps don't give a thumbs down for this since i already mentioned that the people above me have answered his queries. just trying to teach him something.

log [.9375] = n log[0.5]

n= log[.9375]/log[0.5] =0.09310940439148147067594162656279

dosnt matter which base - just use the same one on each number

log 0.9375 = n log 0.5

log 0.9375 / log 0.5 = n

0.0931 = n

it's no help that 0.9375 = 15/16