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Sphere volume problem need math help?

It's a math problem I dont want the answer but I dont know how to set it up. There is a cube in a sphere that each corner touches the sphere. The cube measures up to 200m cubed. Or each leg is 5.8 meters. How do I set it upto find out the volume of the sphere.

3 Answers

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  • 9 years ago
    Favorite Answer

    Find the radius of the sphere.

    sin(45°) = (5.848/2) / r

    r = 4.135

    Volume of sphere = (4/3)π(4.135)³ = 296.2 m³.

  • Find the distance from one corner of the cube to the opposite corner. This will give you the diameter of the sphere

    s^3 = 200

    s = 200^(1/3)

    d^2 = s^2 + s^2 + s^2

    d^2 = 3s^2

    d^2 = 3 * 200^(2/3)

    d = sqrt(3) * 200^(1/3)

    Now, the volume of a sphere is (4/3) * pi * r^3

    r = d/2

    V = (4/3) * pi * (d/2)^3

    V = (4/3) * (1/8) * pi * d^3

    V = (1/2) * (1/3) * pi * (3^(1/2) * 200^(1/3))^3

    V = (1/6) * pi * 3^(3/2) * 200

    V = (3 * 200 / 6) * pi * sqrt(3)

    V = (600 / 6) * pi * sqrt(3)

    V = 100 * sqrt(3) * pi

  • 9 years ago

    More precisely, the length of each side, s, of the cube is cbrt(200). No need to evaluate it yet.

    The length of the diagonal of a cube is given by

    d^2 = 3*s^2

    so the radius of the sphere is

    r = d/2 = (sqrt(3s^2))/2

    s = cbrt(200)

    so volume of the sphere is

    V = (4pi*r^3)/3

    = (4pi*((sqrt(3s^2))/2)^3/2

    = (4pi*((sqrt(3*(cbrt(200))^2))/2)^3)/3

    = 544 m^3

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