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Completeing the Square Help?
My problem is:
9x^2-y^2-18x-6y-9=0
I need to get it into this equation (x-h)^2/a^2 - (y-k)^2/b^2=1
I know a few steps:
9x^2-y^2-18x-6y-9=0
9x^2-18xy^2-6y=9
9(x^2-2x)-(y^2+6y)=9
And then I get stuck. I know I'm supposed to get it to:
9(x^2-2x+1) - (y^2+6y+9)=9+9-9
next, but I don't know how
Any help on this problem would be very appreciated
1 Answer
- William BLv 79 years agoFavorite Answer
9(x^2-2x)-(y^2+6y)=9
9(x^2 -2x+__) - (y^2 +6y + __) =9 +9(__ ) -(__ )
you complete the square by adding half the b term then squaring it
9(x^2 -2x+1) - (y^2 +6y +9) =9 +9(1) - (9)
9(x-1)^2 -(y+3)^2 =9+9-9 =9
(x-1)^2 -(y+3)^2/9 =1
