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Chemitry question: Acetylene derivative?
1. Of the two general types of acetylene derivatives, R-C=C-H and R-C=C-R which would be expected to give a positive test when the reagents Ammoniacal Cuprous Chloride and Ammoniacal Silver nitrate are used?
b. What structural effect or feature is required for the reaction?
c. What is the function of ammonia in these reactions?
2. (Just verifying) What volume of acetylene measured at standard conditions could be obtained from 10 grams of calcium carbide?
*I got the answer 3.8690L... I used .1560mol for n... I'm not sure if I was on the right track xD
thanks :D
2 Answers
- ?Lv 79 years agoFavorite Answer
1. You say this problem is about acetylene derivative .. but the compounds you give only have double, not triple bonds between the C atoms. Is that correct?
2. CaC2 (s)+2H2O(l)=> C2H2(g) + Ca(OH)2 (aq)
molar mass CaC2 = = 40 + (12x2) = 64
64g CaC2 gives 22.4L C2H2 [1 mole] at STP
Use simple proportion
10g CaC2 gives 22.4/64 x 10 = 3.5L C2H2
unfortunately you haven't posted your method here so can't see what you did wrong. even if you use room temp [1 mole gas = 24L] you only get 3.75L not 3.869L although no of mole is 0.15625 .. similar to your figure.
Source(s): rtc - ?Lv 44 years ago
i'm no longer likely particular, yet in assessment to quite a few the previous answerer's i in my opinion understand what your conversing approximately. (kudos to the different answerers who did no longer take this as a humorous hazard for a factor). My advice could be to discover an equation and verify out it. Is there a recognizable function once you get to the derivative of jerk or do you land up with something ridiculous? What could the unit be on the derivative of that? f''''(x) is form of a loopy element of think of roughly once you truly initiate thinking approximately it lol. i haven't taken physics for an prolonged time, so i'm able to no longer think of of a stable occasion, yet once you're asking this then you truly are in all probability nonetheless interior the classification or something. Use a graphing calculator to work out what the function could appear like. in case you truly determine it out could you deliver me a message and enable me understand? Now i'm curious.