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2 Answers
- ?Lv 79 years agoFavorite Answer
If α and β are the roots of
x^2 - 30x + 6,
what is the value of α^2 + β^2?
Vieta’s formulae (Theory of Roots and Equations) state that
if α and β are the roots of the quadratic equation Ax2 + Bx + C,
then α + β = −B/A and α ⋅ β = C/A.
This follows by comparing coefficients of
Ax2 + Bx + C = A(x - α)(x - β) = Ax2 - A(α + β)x + Aα⋅β
α + β = 30
α ⋅ β = 6
(α + β)^2 = 30^2
(α + β)^2 - 2αβ = 900 - 12
α^2 + β^2 = 888
- 9 years ago
x = (30 +/- sqrt(900 - 24)) / 2
x = (30 +/- sqrt(876)) / 2
x = (30 +/- 2 * sqrt(219)) / 2
x = 15 +/- sqrt(219)
a = 15 + sqrt(219)
b = 15 - sqrt(219)
a^2 + b^2 =>
(15 + sqrt(219))^2 + (15 - sqrt(219))^2 =>
225 + 30 * sqrt(219) + 219 + 225 - 30 * sqrt(219) + 219 =>
450 + 438 =>
888