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If α and β are the roots of x^2 - 30x + 6, what is the value of α^2 + β^2?

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  • ?
    Lv 7
    9 years ago
    Favorite Answer

    If α and β are the roots of

    x^2 - 30x + 6,

    what is the value of α^2 + β^2?

    Vieta’s formulae (Theory of Roots and Equations) state that

    if α and β are the roots of the quadratic equation Ax2 + Bx + C,

    then α + β = −B/A and α ⋅ β = C/A.

    This follows by comparing coefficients of

    Ax2 + Bx + C = A(x - α)(x - β) = Ax2 - A(α + β)x + Aα⋅β

    α + β = 30

    α ⋅ β = 6

    (α + β)^2 = 30^2

    (α + β)^2 - 2αβ = 900 - 12

    α^2 + β^2 = 888

  • x = (30 +/- sqrt(900 - 24)) / 2

    x = (30 +/- sqrt(876)) / 2

    x = (30 +/- 2 * sqrt(219)) / 2

    x = 15 +/- sqrt(219)

    a = 15 + sqrt(219)

    b = 15 - sqrt(219)

    a^2 + b^2 =>

    (15 + sqrt(219))^2 + (15 - sqrt(219))^2 =>

    225 + 30 * sqrt(219) + 219 + 225 - 30 * sqrt(219) + 219 =>

    450 + 438 =>

    888

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