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Find the vertex and y-intercept of the quadratic function!?
I have the y - intercept im confused on the vertex.
i came up with (1/2, -1/2) first I found the vertex x value bu using -b/2a, then y by using c-b^2/4a
just want to know is this the correct process and values?
1 Answer
- 9 years agoFavorite Answer
You didn't give the actual equation, but I can tell you how you're doing with the methods you're approaching. The way you found the x-value of the vertex is right. As for the y value, that might be too complicated so what you can just do is plug in the value you got for x into the equation to get the y-value. Then you should get both values for the vertex. Hope this helps :)
