Help me solve algebra word problem PLEASE! :)?

Let t = # of seconds until paint drop hits the ground.

0 = -16t^2 + 0t + 225

16t^2 = 225

t^2 = 225/16

t = 15/4 or t = -15/4

A negative time makes no sense for this problem so discard t = -25/4, leaving just

t = 15/4 sec

There are many ambiguities in this problem. For example, what is the acceleration of gravity in the planet where the construction worker is working? Why do I fart so much? What angle does the paint droplet fall? Does the rain in Spain really stay by the plain? These questions are vital to truly understanding this question. But, nevertheless, I will give you the answer your teacher wants.

We start with on of the equations derived from integrating the definitions of velocity and acceleration with respect to position. That is, s = ut + (1/2) gt^2

Here, s is the distance, t is time, u is initial velocity of the object (in this case, the paint droplet) and g is the acceleration due to gravity. We have u = 0, as initially the paint droplet has no velocity.

Hence, the equation becomes, s = (1/2)gt^2. g = 32 m/s^2 on earth, and s = 225 feet. Solving 225 = (1/2)(32)t^2 for t, we have t = +/- 3.74 seconds. We take the positive root (a convention for time) and have t = 3.74 seconds.

Alternatively, we could use a relativistic approach, but since the velocity of such an object is so small compared to the speed of light, it won't really make a noticeable difference in our answer.

s = ut + (1/2) at^2

Acceleration under gravity is 32.174 feet per second.

Initial velocity zero since the paint drops, therefore it had no initial velocity. Therefore the ut bit is dropped from the equation since anything times zero.

s = (1/2) at^2

2s = at^2

2s/a = t^2

but s = 225 feet.

2*225/32.174 = t^2

450/32.174 = t^2

13.986448685273823584260583079505 = t^2

3.7398460777515728640903262112341 = t^2

Let's round to 3 sig figs to match the accuracy of the question.

3.74 seconds is your answer.

Actually this is not a terrible question, it's actually quite easy to solve it's just placed under the wrong section, it assumes a knowledge of physics and if it was posted under physics there would have been probably 20 answers all saying the same thing by now.

you know ..

it doesn't matter how heavy it is..

if you don't consider the air ...

it follows this rule :

X=1/2a * t^2

X is the whole movement

a = 10 m/s^2

t is the time of the movement..

so .. because a is using meter we have to convert the height to meter ..

225 feet =68.58 meters

so the whole movement is 68.58 meters

and the a= 10

so we put the numbers in formula..

68.58=1/2 * 10 * t^2

so >> 13.71=t^2 >>t=3.7 seconds

but actualy this formula is more complex but i didn't want you to get confused..

the whole formula is X=1/2a * t^2 + vt + x

v is used when we shoot it or we git some primary speed

and x is kinda same too X but with a little different..

your 2 numbers are: x and x+35. to locate the numbers, plug them into the formula. that could finally end up to be: 2(x+35) - x=87 (multiply 2 with each and every volume contained in the parenthesis) 2x + 70 -x=87 (subtract 70 from both side) x=17 So your 2 numbers are 17 and fifty 2(were given fifty 2 from 35+17) desire that this helps.

x = vt + 0.5at^2

v = 0 ft/sec initial velocity

This cancels out the vt term.

x = 0.5at^2

Solve the equation for t.

2x = at^2

t^2 = 2x/a

t = SQRT (2x/a)

a = 32 ft/sec^2 gravitational acceleration

x = 225 ft distance fallen

t = 3.75 sec elapsed time

Depends on how heavy the paint is

This is a terrible word problem. There absolutely isn't enough information to answer it.