Need help with this equation?

I assume you mean 2√(x + 1) - 4 = 0

=> 2√(x + 1) = 4

=> √(x + 1) = 2

=> x + 1 = 4

i.e. x = 3

:)>

2(sqrt)x+1-4=0

what is in the sqrt? is it this:

2√(x+1)-4 =0

if it is...

2√(x+1)=+4

√(x+1)=4/2

√(x+1)²=2²

x+1 = 4

x = 3

Squaring a square root will leave you with what is inside.

Generally you get rid of square roots by squaring them, so first isolate the square root.

2(sqrt)x = +4 - 1

2(sqrt)x = 3

(sqrt)x = 3/2

Now square both sides

x = (3/2)^2

x = 9/4

To get rid of the square root you square the actual root, then use the distributive rooster to the opposite side, canceling out thE square, then keeping 0 the same.

2√ (x +1) - 4 = 0

-------------------------

..............+4...+4

2√ (x+1)x = 4

-------..........---

2................2

(√ x+1)^2= (2)^2

x+1 = 4

-------------

-1......-1

x = 3

My dear asker!

Mathematical statements must be written in clear way ... so that the answering person need no assumption to make himself.