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EM MD
Lv 5
EM MD asked in Science & MathematicsMathematics · 9 years ago

Find a polar equation for the curve represented by the given Cartesian equation.?

Find a polar equation for the curve represented by the given Cartesian equation.

xy=9

i don't even know where to start... i get that you have to plug in (rcostheta)(rsintheta)=9

but lost from there.

please help?

3 Answers

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  • Cal65
    Lv 5
    9 years ago
    Favorite Answer

    x=rsin(u)

    y=rcos(u)

    r^2(sin(u)*cos(u))=9

    IDENTITY==> 2sinu*cosu=sin(2u)

    r^2*sin(2u)/2=9

    r^2*sin(2u)=18

    r^2=18csc(2u)

    r^2=18csc(2*theta)

  • Brenda
    Lv 7
    9 years ago

    xy=9

    remember that x=rcosθ and y=rsinθ so:

    (rcosθ)*(rsinθ)=9

    r²sinθcosθ =9

    2r²sinθcosθ=18

    r²(sin2θ)=18

    r² =18/sin2θ =>18csc2θ

  • Anonymous
    9 years ago

    um.. it's.. uh..

    Well, there's that... hmm..

    I know! its impossible

    http://www.youtube.com/watch?v=mcUPIAIpdXI

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